Which is most likely to be part of an ionic bond?

A. An atom with no valence electrons
B. An atom with one valence electron
C. An atom with two valence electrons
D. An atom with three valence electrons

I think it is B.

Jai Jai answered
9 years ago

Yes it's B. :)

M M answered
9 years ago

Thank you Jai :)

can i get some answers please

Hal Hal answered
5 years ago

1. B

2. A,D
3. B,D,E
4. D
5. C,D,E
6. A,B
7. C
8. B
9. B
10. D

Lu Lu answered
5 years ago

Thanks Hal!

ogga chagga ogga chagga answered
5 years ago

literally love this site thanks hal

Algebra student Algebra student answered
5 years ago

hal is correct

*welp* *welp* answered
4 years ago

thx It helped a lot!!!!!

<33 <33 answered
3 years ago

if you guys have the assessment with only 9 questions use hal’s answers but skip number 2. he is completely right

Explain Bot Explain Bot answered
7 months ago

To determine which atom is most likely to be part of an ionic bond, we need to understand the concept of valence electrons. Valence electrons are the outermost electrons in an atom's electron cloud and are involved in chemical bonding.

In an ionic bond, one atom gives up or loses electrons, while the other atom gains or accepts those electrons. This transfer of electrons occurs between atoms with different electronegativities, resulting in the formation of ions, which are charged species.

To identify the most likely atom to be part of an ionic bond, we need to look for an atom that has a tendency to lose or gain electrons.

Now, let's analyze the options provided:

A. An atom with no valence electrons: Since valence electrons are crucial in the formation of ionic bonds, an atom with no valence electrons is highly unlikely to be part of an ionic bond. Therefore, we can eliminate this option.

B. An atom with one valence electron: This atom has a tendency to lose the single valence electron to achieve stability. Losing an electron would result in a positive charge, and this cation would be attracted to a negatively charged anion in an ionic bond. Therefore, option B is a possible candidate.

C. An atom with two valence electrons: Atoms with two valence electrons are not likely to be part of an ionic bond. Elements with two valence electrons typically form covalent bonds (sharing of electrons) instead of ionic bonds. Hence, we can eliminate this option.

D. An atom with three valence electrons: Similarly to atoms with two valence electrons, atoms with three valence electrons also tend to form covalent bonds rather than ionic bonds. Hence, we can eliminate this option as well.

Based on the analysis above, option B (an atom with one valence electron) is the most likely to be part of an ionic bond.

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