# a rock is dropped from a high brige.at the end of 3 seconds of free fall the speed of the rock is:[in centimeters per second,g=10 m/second square]

## V=u+gt

u=0
V=0+9.8×3 (g=9.8)
=29.4m/s
.
1m/s = 100m/s
29.4×100
=2940 cm/s

## Well, dropping a rock from a high bridge sounds like quite the "fall"onious act! Let's calculate the speed of the rock after 3 seconds of free fall.

Given that the acceleration due to gravity is 10 m/s^2, after 3 seconds we can use the formula for velocity:

v = u + gt

Where:
v = final velocity
u = initial velocity (which is 0 in this case since the rock is dropped)
g = acceleration due to gravity
t = time (3 seconds)

Plugging in the values:

v = 0 + (10 m/s^2) * (3 s)

v = 30 m/s

But you asked for the speed in centimeters per second. Since 1 meter is equal to 100 centimeters, let's convert the speed:

30 m/s * 100 cm/m = 3000 cm/s

Therefore, after 3 seconds of free fall, the speed of the rock is 3000 centimeters per second. Quite a speedy rock if you ask me! Keep an eye out below!

## To determine the speed of the rock at the end of 3 seconds of free fall, we can use the equation for free fall motion:

v = gt

Where:
v = final velocity (speed) of the rock
g = acceleration due to gravity (10 m/s^2)
t = time (3 seconds)

To convert the final velocity to centimeters per second (cm/s), we also need to convert the units:

1 meter = 100 centimeters

Now we can calculate the speed of the rock:

v = gt
= 10 m/s^2 * 3 s
= 30 m/s

To convert from meters per second to centimeters per second:

30 m/s * 100 cm/m = 3000 cm/s

Therefore, the speed of the rock at the end of 3 seconds of free fall is 3000 centimeters per second.

## To find the speed of the rock after 3 seconds of free fall, we need to use the formula for the final velocity of an object in free fall:

vf = vi + gt

Where:
vf is the final velocity
vi is the initial velocity (which is zero in this case because the rock is dropped)
g is the acceleration due to gravity (given as 10 m/s²)
t is the time in seconds

Using this formula, let's calculate the final velocity:

vf = 0 + (10 m/s²) * (3 s)
vf = 0 + 30 m/s

Since we want the speed in centimeters per second, we need to convert the final velocity from meters per second to centimeters per second. There are 100 centimeters in 1 meter, so:

vf = 30 m/s * (100 cm/1 m)
vf = 3000 cm/s

Therefore, the speed of the rock after 3 seconds of free fall is 3000 centimeters per second.