# the speed of an object at the end of 4 successive seconds is 20,25,30 and 35 meters per second,respectively.the acceleration of this object is?

## V=20 m/s

T=4s
A=20/4
=5m/s2
For 25 m/s we know that in 1 second 5 m/s velocity increase for this case we will add 1 second in 4,
=25/5=5m/s2
Same case; 30 and 5seconds plus 1 second=6seconds
=30/6=5m/s2
For 35 we will ad 6+1=7 seconds
=35/7=5m/s2
Hence the over all resultant is 5 m/s2
Aijaz ali

## To determine the acceleration of an object, we need to use the formula for acceleration:

Acceleration (a) = (Final velocity - Initial velocity) / Time

Given that the object's final velocities after 4 successive seconds are 20, 25, 30, and 35 meters per second, respectively, we can compute the acceleration.

First, let's calculate the initial velocity. Since we don't have that information in the question, we can assume it to be zero (unless otherwise specified). So, the initial velocity (u) is 0 m/s.

Now, we can calculate the acceleration for each time interval:

For the first 4-second interval:
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration1 = (20 m/s - 0 m/s) / 4 s
Acceleration1 = 20 m/s / 4 s
Acceleration1 = 5 m/s²

For the second 4-second interval:
Acceleration2 = (25 m/s - 20 m/s) / 4 s
Acceleration2 = 5 m/s / 4 s
Acceleration2 = 1.25 m/s²

For the third 4-second interval:
Acceleration3 = (30 m/s - 25 m/s) / 4 s
Acceleration3 = 5 m/s / 4 s
Acceleration3 = 1.25 m/s²

For the fourth 4-second interval:
Acceleration4 = (35 m/s - 30 m/s) / 4 s
Acceleration4 = 5 m/s / 4 s
Acceleration4 = 1.25 m/s²

Therefore, the acceleration of the object is constant throughout the 4 successive seconds, and its value is 1.25 m/s².