# In the following reaction, how many liters of carbon dioxide will be produced if 250 liters of oxygen is used in the combustion of sucrose given that both gases are at STP?

C12H22O11 + 1202 -> 12CO2 + 11H2O

I have had other ones in my homework that were very easy but this one is a hard one for me and I don't understand...

## When using gases one may use liters directly as if they were mols.

250 L O2 x (12 mols CO2/12 mols O2) = 250 x 12/12 = 250 L CO2 produced.

## To determine the number of liters of carbon dioxide produced in the given reaction, you need to use the stoichiometry of the balanced equation. Here's a step-by-step explanation of how to solve the problem:

Step 1: Balance the equation
The first step is to ensure that the equation is balanced. The balanced equation you provided is correct:

C12H22O11 + 12O2 -> 12CO2 + 11H2O

Step 2: Determine the molar ratio
Next, look at the balanced equation and determine the mole ratio between oxygen (O2) and carbon dioxide (CO2). From the balanced equation, you can see that for every 12 moles of oxygen used, 12 moles of carbon dioxide are produced.

Step 3: Convert liters to moles
To find the number of moles of oxygen used, you can use the ideal gas law at STP (Standard Temperature and Pressure). At STP, one mole of any gas occupies 22.4 liters. Therefore, if you have 250 liters of oxygen, you can convert it to moles by dividing by 22.4:

250 L O2 × (1 mol O2 / 22.4 L O2) ≈ 11.16 mol O2

Step 4: Calculate the moles of carbon dioxide produced
Based on the ratio from the balanced equation (12 moles of oxygen to 12 moles of carbon dioxide), you can determine the moles of carbon dioxide produced:

11.16 mol O2 × (12 mol CO2 / 12 mol O2) = 11.16 mol CO2

Step 5: Convert moles to liters
Finally, using the ideal gas law at STP, you can convert the moles of carbon dioxide to liters:

11.16 mol CO2 × (22.4 L CO2 / 1 mol CO2) = 249.984 L CO2

Rounding to the appropriate number of significant figures, the volume of carbon dioxide produced is approximately 250 liters.

Note: The slight discrepancy between your given oxygen volume (250 L) and the resulting carbon dioxide volume (approximately 250 L) is due to rounding errors during the conversions.