# What is an equation in slope-intercept form for the line that passes through the points (1,-3(), (3,1)?

## y=mx+b

a) -3=m+b
b) 1=3m+b

subtract the equatons
-4=-2m
m=1/2

put that into either a or b, and solve for b.

## To find the equation of a line in slope-intercept form, you need two pieces of information: the slope of the line and the y-intercept.

Step 1: Calculate the slope (m):
The slope of a line passing through two points (x1, y1) and (x2, y2) can be found using the formula:
m = (y2 - y1) / (x2 - x1)

Using the given points (1, -3) and (3, 1):
m = (1 - (-3)) / (3 - 1)
m = 4 / 2
m = 2

Step 2: Determine the y-intercept (b):
The y-intercept is the point where the line intersects the y-axis. We can find it by substituting one of the points into the slope-intercept form equation: y = mx + b.

Using the point (1, -3):
-3 = 2(1) + b
-3 = 2 + b
b = -5

Step 3: Write the equation in slope-intercept form:
Now that we have the slope (m = 2) and the y-intercept (b = -5), we can write the equation in slope-intercept form: y = mx + b.

Therefore, the equation in slope-intercept form for the line passing through the points (1, -3) and (3, 1) is y = 2x - 5.