Show how to calculate the molarity of 45 g of hcl in 1.5 L of water

mols HCl = grams/molar mass

M HCl = mols HCl/L HCl = ?

so the answer is 45/1.5=30

No. 45 g is not 45 mols. mols = grams HCl/molar mass HCl as I posted above. THEN, M = mols/1.5 = ?


See my answer above.

45g/36.5g/mol= 1.233mola*1000/1500= 0.822M

To calculate the molarity (M) of a solution, we need to know the moles of solute dissolved in a certain volume of solvent. In this case, we want to find the molarity of 45 g of HCl in 1.5 L of water. Here's how you can do that:

Step 1: Convert grams of HCl to moles.
To convert grams to moles, we need to know the molar mass of HCl. The molar mass of HCl is 36.46 g/mol (1 atomic mass unit of hydrogen + 35.46 atomic mass units of chlorine).

To find the moles of HCl, divide the mass by the molar mass:
moles = mass / molar mass
moles = 45 g / 36.46 g/mol
moles ≈ 1.23 moles

Step 2: Convert liters of water to moles of water.
Since there are no solute particles in 1.5 liters of water (H2O) (assuming it is pure water), we can assume the number of moles of water is equal to its volume in liters. Therefore, in this case, we have 1.5 moles of water.

Step 3: Calculate the molarity.
Now that we have the moles of HCl (1.23 moles) and the moles of water (1.5 moles), we can calculate the molarity using the following formula:
M = moles of solute / liters of solution
M = 1.23 moles / 1.5 L
M ≈ 0.82 M

Thus, the molarity of a solution containing 45 g of HCl in 1.5 L of water is approximately 0.82 M.