# a proton is projected perpendicularly into a magntic field that has a magnitude of 0.05T. the field is then adjusted so that an electron will follow a circular path of the same radius when it is projected perpendicularly

## To determine the necessary adjusted magnetic field for an electron to follow a circular path with the same radius as a proton in the original magnetic field, we need to consider the relationship between the magnetic field, the charge of the particle, and the radius of its circular path.

The formula for the magnetic force on a charged particle moving perpendicular to a magnetic field is given by:

F = q * v * B

Where:
F is the magnetic force,
q is the charge of the particle,
v is the velocity of the particle, and
B is the magnetic field strength.

In the case of a circular path, the magnetic force provides the necessary centripetal force to keep the particle in its circular motion. This means that the magnetic force is equal to the centripetal force:

F = mv^2 / r

Where:
m is the mass of the particle, and
r is the radius of the circular path.

For an electron, the charge is -1.6 x 10^-19 C, while for a proton, the charge is +1.6 x 10^-19 C. The masses are different too, but for this problem, we can ignore the mass difference because the question specifies that the radii are the same.

Now, for the proton, we have:

Fp = (q_p * vp * B) = mp * vp^2 / rp

For the electron, we want to find the adjusted magnetic field Be such that:

Fe = (q_e * ve * Be) = me * ve^2 / rp

Since the radii are the same, we can set up an equation using the ratio of the proton and electron charges:

(q_p * vp * B) / (q_e * ve * Be) = (mp * vp^2) / (me * ve^2)

Substituting the values given for the proton charge (q_p) and electron charge (q_e), we get:

(vp * B) / (ve * Be) = (mp * vp^2) / (me * ve^2)

Since we want to find the value of the adjusted magnetic field Be, we can rearrange the equation as follows:

Be = (vp * B * me * ve^2) / (mp * vp^2)

Now, plug in the known values:
vp = ve (since both particles are projected perpendicularly into the magnetic field),
B = 0.05 T (the original magnetic field magnitude),
And use the known values for the masses of the proton (mp) and electron (me).

Finally, calculate the adjusted magnetic field Be using the formula above, and you'll have the answer.