If a building contractor hires 5 day laborers and 2 concrete finishers, his payroll for the day is $1200. If he hires i day laborer and 4 concrete finishers, his daily cost is $924. Find the daily wage for each type of worker.
5L+2C=1200
1L+4C=924
does that help?
To find the daily wage for each type of worker, we can use a system of equations.
Let's assume the daily wage for a day laborer is "D" and the daily wage for a concrete finisher is "C".
According to the given information, when the contractor hires 5 day laborers and 2 concrete finishers, the payroll for the day is $1200. This can be represented as the equation:
5D + 2C = 1200 (Equation 1)
Similarly, when the contractor hires 1 day laborer and 4 concrete finishers, the daily cost is $924, which can be represented as:
1D + 4C = 924 (Equation 2)
Now, we need to solve this system of equations to find the values of D and C.
Multiplying equation 2 by 5, we get:
5D + 20C = 4620 (Equation 3)
Now, we can subtract equation 1 from equation 3 to eliminate the 'D' term:
(5D + 20C) - (5D + 2C) = 4620 - 1200
18C = 3420
Dividing both sides of the equation by 18, we find:
C = 190
Substituting the value of C back into equation 1, we can solve for D:
5D + 2(190) = 1200
5D + 380 = 1200
5D = 1200 - 380
5D = 820
Dividing both sides of the equation by 5, we find:
D = 164
Therefore, the daily wage for each day laborer is $164 and the daily wage for each concrete finisher is $190.