# If a building contractor hires 5 day laborers and 2 concrete finishers, his payroll for the day is \$1200. If he hires i day laborer and 4 concrete finishers, his daily cost is \$924. Find the daily wage for each type of worker.

1L+4C=924

does that help?

## To find the daily wage for each type of worker, we can use a system of equations.

Let's assume the daily wage for a day laborer is "D" and the daily wage for a concrete finisher is "C".

According to the given information, when the contractor hires 5 day laborers and 2 concrete finishers, the payroll for the day is \$1200. This can be represented as the equation:

5D + 2C = 1200 (Equation 1)

Similarly, when the contractor hires 1 day laborer and 4 concrete finishers, the daily cost is \$924, which can be represented as:

1D + 4C = 924 (Equation 2)

Now, we need to solve this system of equations to find the values of D and C.

Multiplying equation 2 by 5, we get:

5D + 20C = 4620 (Equation 3)

Now, we can subtract equation 1 from equation 3 to eliminate the 'D' term:

(5D + 20C) - (5D + 2C) = 4620 - 1200

18C = 3420

Dividing both sides of the equation by 18, we find:

C = 190

Substituting the value of C back into equation 1, we can solve for D:

5D + 2(190) = 1200

5D + 380 = 1200

5D = 1200 - 380

5D = 820

Dividing both sides of the equation by 5, we find:

D = 164

Therefore, the daily wage for each day laborer is \$164 and the daily wage for each concrete finisher is \$190.