# Joyce and Efua are skating. Joyce pushes Efua, whose mass is 40.0 kg, with a force of 5.0 N. What is Efua's Resulting acceleration?

## To find Efua's resulting acceleration, we can use Newton's second law of motion, which states that the force F acting on an object is equal to the mass m of the object multiplied by the acceleration a:

F = m * a

In this case, the force acting on Efua is 5.0 N and her mass is 40.0 kg. So we can rearrange the equation to solve for acceleration:

a = F / m

Substituting the given values, we have:

a = 5.0 N / 40.0 kg

Now we can calculate the resulting acceleration:

a = 0.125 m/s^2

## To find Efua's resulting acceleration, we can apply Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. The equation for Newton's second law is:

F = ma

Where F is the net force, m is the mass, and a is the acceleration.

Given:

Net force (F) = 5.0 N

Mass (m) = 40.0 kg

We can rearrange the equation to solve for acceleration:

a = F / m

Substituting the given values:

a = 5.0 N / 40.0 kg

a = 0.125 m/s^2

Therefore, Efua's resulting acceleration is 0.125 m/s^2.

## F=ma

m=F/m