# Fe walked 9/20(9 over 20) km,Beth walked twice as much as Fe,and Tina walked as much as Fe and 2/20(2 over 20) km. more.Who walked the farthest?How many kilometers did the 3 girls walk?

## Fe = 9/20

Beth = 2(9/20) = 18/20
Tina = 9/20 + 2/20 = 11/20

I think the questions can now be easily answered.

## To determine who walked the farthest, we first need to find the distances walked by each girl.

Given:
Fe walked 9/20 km.
Beth walked twice as much as Fe.
Tina walked as much as Fe plus 2/20 km more.

To find the distance Beth walked:
Beth = 2 * Fe

To find the distance Tina walked:
Tina = Fe + 2/20

Now we can substitute the value of Fe into the equations to find the distances walked by Beth and Tina:

Beth = 2 * (9/20)
Beth = 18/20
Beth = 9/10 km

Tina = (9/20) + (2/20)
Tina = 11/20 km

Now that we have the distances walked by each girl, we can determine who walked the farthest.

Comparing the distances:
Fe = 9/20 km
Beth = 9/10 km
Tina = 11/20 km

From the given distances, it is clear that Beth walked the farthest, covering a distance of 9/10 km.

To find the total distance walked by the three girls, we sum up their individual distances:

Total distance = Fe + Beth + Tina
Total distance = (9/20) + (9/10) + (11/20)
Total distance = (18/40) + (36/40) + (22/40)
Total distance = 76/40
Total distance = 1.9 km

Therefore, the three girls walked a total of 1.9 kilometers.