# what is the molar concentration of h2so4 solution is 2.0ml of which is completely neutralized by 45.0ml of 0.115 mol/L NaOH solution?

## H2SO4 + 2NaOH ==> 2H2O + Na2SO4

mols NaOH = M x L = ?
Note that mols H2SO4 = 1/2 mols NaOH
Then M H2SO4 = mols H2SO4/L H2SO4.

## H2SO4 + 2 NaOH = 2 H2O + Na2SO4

V H2SO4 = 0.025L since you divide it by 1000 to get L
C H2SO4= ?
V NaOH = 0.045L
C NaOH = 0.115

First find the moles for NaOH to find moles you do n= C*V
n= 0.115*0.045
n= 0.005175
Now do molar ratios
H2SO4 1 x
-------- = --- = ---------
NaOH 2 0.005175

x= 1*0.005175
----------
2
x= 0.025875

That is number of H2SO4 moles

now final step find the concentration
C= n/v
C= 0.025875
----------
0.025
C= 1.035 mol/L

therefore the answer is 1.035 mol/L

## To find the molar concentration of the H2SO4 solution, we can use the concept of stoichiometry and the balanced chemical equation for the neutralization reaction between H2SO4 and NaOH.

The balanced chemical equation for the reaction is:

H2SO4 + 2NaOH → Na2SO4 + 2H2O

From the balanced equation, we can see that 1 mole of H2SO4 reacts with 2 moles of NaOH.

Given that 45.0 mL of 0.115 mol/L NaOH solution completely neutralizes 2.0 mL of the H2SO4 solution, we can use the stoichiometry of the reaction to find the moles of H2SO4.

First, let's convert the volume of NaOH solution to moles:

Moles of NaOH = concentration of NaOH × volume of NaOH solution
= 0.115 mol/L × 0.045 L
= 0.005175 mol

Since 1 mole of H2SO4 reacts with 2 moles of NaOH, we can determine the moles of H2SO4:

Moles of H2SO4 = 0.005175 mol/2
= 0.0025875 mol

Finally, we can calculate the molar concentration of the H2SO4 solution:

Molar concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4 solution
= 0.0025875 mol / 0.002 L
= 1.29375 mol/L

Therefore, the molar concentration of the H2SO4 solution is approximately 1.29 mol/L.