# You create a plot of T2 (in s2) vs mass (in kg) and the linear fit of your graph gives a slope of 0.12735 ± 0.01234. What is the value of the spring constant you took the data with?

i am not sure what to do. i know the k=1/slope but im not sure how to start to solve this. its for a final exam review so id appreciate any help with solving this.

## To solve this problem, you can use the relationship between the spring constant (k) and the slope of the linear fit in the plot. The formula is indeed k = 1/slope.

Here's how you can solve it step by step:

1. Start with the equation k = 1/slope.

2. Substitute the given value of the slope into the equation: slope = 0.12735 ± 0.01234.

3. Calculate the value of the spring constant using the formula k = 1/slope:

k = 1 / 0.12735 ± 0.01234

To calculate the exact value of k, you need to use the formula with both the upper and lower bounds of the slope:

k_upper = 1 / (0.12735 - 0.01234)

k_lower = 1 / (0.12735 + 0.01234)

Calculate both values:

k_upper ≈ 7.848

k_lower ≈ 6.916

Therefore, based on the given slope, the spring constant can have a value between approximately 6.916 N/m and 7.848 N/m.

Remember to double-check the units in order to have consistent results.