# The windpipe of a whooping crane is about 1.27 m long. Assuming that the pipe is closed at one end, what is the fundamental frequency of this pipe? Answer in Hz and use 340 m/s for the speed of sound.

## To find the fundamental frequency of a closed-end pipe, we can use the formula:

f = v / (4L),

where f is the fundamental frequency, v is the speed of sound, and L is the length of the pipe.

In this case, the length of the windpipe is given as 1.27 m, and the speed of sound is given as 340 m/s. We can substitute these values into the formula to calculate the fundamental frequency:

f = 340 / (4 × 1.27).

Performing the calculations:

f = 340 / 5.08

f ≈ 66.93 Hz.

Therefore, the fundamental frequency of the windpipe of a whooping crane is approximately 66.93 Hz.

## To find the fundamental frequency of a closed pipe, we can use the formula:

f = V/4L

Where:

f is the fundamental frequency,

V is the speed of sound, and

L is the length of the windpipe.

Given that the speed of sound is 340 m/s and the length of the windpipe is 1.27 m:

f = 340 / (4 * 1.27)

Calculating this equation, we get:

f ≈ 67.32 Hz

Therefore, the fundamental frequency of the windpipe of a whooping crane is approximately 67.32 Hz.