# Find the capacitance of a parallel plate capacitor if 1400 ìC of charge are deposited on its

plates when 20 V are applied across the plates.

## capacitance = charge/unit voltage

C = coulombs / volts

## To find the capacitance of a parallel plate capacitor, you can use the formula:

C = Q / V

Where:

C is the capacitance,

Q is the charge on the plates, and

V is the voltage applied across the plates.

In this case, the charge on the plates is given as 1400 ìC and the voltage applied across the plates is given as 20 V. Plugging these values into the formula:

C = 1400 ìC / 20 V

To ensure consistent units, convert ìC to coulombs (C):

1 ìC = 10^-6 C

C = (1400 * 10^-6 C) / 20 V

C = 0.07 * 10^-3 F

C = 70 * 10^-6 F

Therefore, the capacitance of the parallel plate capacitor is 70 * 10^-6 F.

## To find the capacitance of a parallel plate capacitor, you can use the formula:

C = Q / V

Where:

C is the capacitance of the parallel plate capacitor,

Q is the charge deposited on its plates, and

V is the voltage applied across the plates.

In this case, you are given that the charge deposited on the plates is 1400 ìC (microcoulombs) and the voltage applied across the plates is 20 V. Now you can simply substitute these values into the formula to find the capacitance:

C = 1400 ìC / 20 V

To ensure that the units are consistent, you need to convert microcoulombs (ìC) to coulombs (C):

1 ìC = 1 x 10^-6 C

Therefore:

C = (1400 ìC x 1 x 10^-6 C/1 ìC) / 20 V

Simplifying the above expression:

C = 0.07 C / 20 V

C = 0.0035 F

So, the capacitance of the parallel plate capacitor is 0.0035 F (Farads).