# . If f(x) = {x^2+3x-1, x<=2 and -3bx+3, x<2 , find the value of b in order for f to be continuous

## well we need the limit from both sides to be the same.

f(2) = 2^2+3*2-1 = 9

So, we need

-3bx+3 = 9 when x=2

-3b*2+3 = 9

-6b = 6

b = -1

f(2) = 2^2+3*2-1 = 9

So, we need

-3bx+3 = 9 when x=2

-3b*2+3 = 9

-6b = 6

b = -1