A 813. mL sample of argon gas at 452. K is cooled at constant pressure until the volume becomes 356. mL. What is the new gas temperature in Kelvin?
PV=PV
.813L*452=.356X
There is no P listed and the formula is not PV = PV. However the answer is correct.
It is (V1/T1) = (V2/T2)
(813/452) = (356/T2)
T2 = 813*452/356
To find the new gas temperature in Kelvin, we can use the combined gas law formula:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure
V1 = initial volume
T1 = initial temperature
P2 = final pressure (since the pressure is constant, P2 = P1)
V2 = final volume
T2 = final temperature (we need to find this)
Given:
V1 = 813 mL
T1 = 452 K
V2 = 356 mL
Let's plug in the known values into the formula and solve for T2:
(P1 * V1) / T1 = (P2 * V2) / T2
Since P2 = P1:
(V1) / T1 = (V2) / T2
Now rearrange the equation to solve for T2:
T2 = (V2 * T1) / V1
Substitute the given values:
T2 = (356 mL * 452 K) / 813 mL
Simplify:
T2 ≈ 198 K
Therefore, the new gas temperature is approximately 198 Kelvin.