A bullet is fired straight up from a gun with a
muzzle velocity of 208 m/s.
Neglecting air resistance, what will be its
displacement after 2.6 s? The acceleration of
gravity is 9.8 m/s2 .
D = Vo*t + 0.5g*t^2
D = 208*2.6 - 4.9*2.6^2 =
To find the displacement of the bullet after 2.6 seconds, you can use the kinematic equation:
s = ut + (1/2)at^2
where:
- s is the displacement
- u is the initial velocity
- t is the time
- a is the acceleration
In this case:
- u = 208 m/s (muzzle velocity)
- t = 2.6 s
- a = -9.8 m/s^2 (negative since acceleration due to gravity is acting in the opposite direction to motion)
Substituting these values in the equation, we get:
s = (208 m/s) * (2.6 s) + (1/2) * (-9.8 m/s^2) * (2.6 s)^2
Calculating this expression will give us the displacement of the bullet after 2.6 seconds.