A ballon is filled with 54.8 g of CO2. The gas is at STP. Calculate the volume of the CO2 gas in liters?
mols CO2 = grams/molar mass = ?
Then mols CO2 x (22.4L/mol) = ? L
To calculate the volume of CO2 gas at STP (Standard Temperature and Pressure), we need to use the Ideal Gas Law equation:
PV = nRT
Where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
Given that the gas is at STP, the pressure (P) is 1 atm, and the temperature (T) is 273 K.
To calculate the number of moles (n), we need to use the molar mass of CO2, which is 44.01 g/mol.
n = molar mass / mass
n = 44.01 g/mol / 54.8 g
Now we can substitute the known values into the Ideal Gas Law equation:
(1 atm) * V = (54.8 g) / (44.01 g/mol) * (0.0821 L·atm/(mol·K)) * (273 K)
Simplifying:
V = (54.8 g) / (44.01 g/mol) * (0.0821 L·atm/(mol·K)) * (273 K) / (1 atm)
Calculating:
V ≈ 24.6 L
Therefore, the volume of CO2 gas at STP is approximately 24.6 liters.