I would double the first then add that to the 2nd to get
8x = 32
x =4
sub into the first:
12 + 2y = 14
2y = 2
y = 1
x=4, y =1
check by subbing those values into both equations, they should work
answer:
3x+2y=14
2x-4y=4
8x = 32
x =4
sub into the first:
12 + 2y = 14
2y = 2
y = 1
x=4, y =1
check by subbing those values into both equations, they should work
first of all , it is very difficult to write it in matrix form in this format,
so you would have the matrix
3 2
2-4 multiplied by the column matrix
x
y
=
14
4
I will assume you know how to find the inverse of a 2by2 matrix, and how to multiply matrices
the inverse of our 2by2 is
1/4 1/8
1/8 -3/16
so
1/4 1/8
1/8 -3/16
multiplied by
14
4
gives us
4
1
Let's solve the first equation for x:
3x + 2y = 14
Rearranging the equation:
3x = 14 - 2y
x = (14 - 2y) / 3
Now substitute this expression for x into the second equation:
2x - 4y = 4
Substitute (14 - 2y) / 3 for x:
2((14 - 2y) / 3) - 4y = 4
Simplify and solve for y:
(28 - 4y) / 3 - 4y = 4
28 - 4y - 12y = 12
28 - 16y = 12
-16y = 12 - 28
-16y = -16
y = (-16) / (-16)
y = 1
Now substitute the value of y into the first equation to solve for x:
3x + 2(1) = 14
3x + 2 = 14
3x = 14 - 2
3x = 12
x = 12 / 3
x = 4
So the solution to the system of equations is x = 4 and y = 1.