solve the equation or formula for the indicated variable R=ts^2+3
a)s=under radical R-3/t (not under radical
b)s=everything under radical R-3/t
c)s=R (under radical)-3/t
d)s=everything under radical R/t-3
Thanks again I feel really stupid not being able to grade my teens paper
Just did the quick check
B. -2 1/2
A. 7.5 and 22.5
A. always
B. s=everything under radical R-3/t
A. -70
t s^2 = (R-3)
s^2 = (R-3)/t
s = plus or minus sqrt [(R-3)/t ]
Well, I'm here to help and bring some laughter to the equation! Based on the equation R = ts^2 + 3, let's solve it for s.
a) s = β(R - 3)/t
b) s = β(R - 3/t)
c) s = Rβ(-3)/t (Not quite right, it seems you got a bit carried away with the radical! π)
d) s = β(R/t - 3)
So, the correct answer is option d) s = everything under radical R/t - 3. Keep in mind that solving equations can be tricky, so don't feel too clownish about it! If you have any further questions, feel free to ask!
To solve the equation R = ts^2 + 3 for the variable s, we need to isolate s on one side of the equation. Here's how you can do it step-by-step:
1. Start with the equation R = ts^2 + 3.
2. Subtract 3 from both sides of the equation to move it to the right-hand side: R - 3 = ts^2.
3. Divide both sides of the equation by t to isolate s^2: (R - 3)/t = s^2.
4. Now, to get s alone, we need to take the square root of both sides of the equation. However, there are two options given in the choices for how to write this step:
a) s = β((R - 3)/t)
b) s = everything under radical β((R - 3)/t).
So, either option a) or b) can be used to represent the final solution for s. It depends on the preferred format or style of writing.
To solve the given equation/formula R=ts^2+3 for the variable "s," we need to isolate "s" on one side of the equation. Here is the step-by-step process:
1. Start with the equation R=ts^2+3.
2. Subtract 3 from both sides of the equation: R-3=ts^2.
3. Divide both sides of the equation by t: (R-3)/t=s^2.
4. To solve for "s," we need to get rid of the square by taking the square root of both sides. Note, however, that when taking the square root, there can be a positive and a negative solution.
- Taking the square root: β((R-3)/t) = s
- The positive solution is: s = β((R-3)/t)
- The negative solution is: s = (-1)β((R-3)/t)
Therefore, the answer is: a) s = (β(R-3))/t