Using the intercepts to graph the equation
X + 5y = 10
What points would I plot on the graph?
when x = 0, the line hits the y axis at y = 2
so (0,2) is a point
when y = 0, the line hits the x axis at x = 10
so (10,0) is a point.
The equation is that of a straight line, so draw a line that goes through those two points.
2x + 5y=10
To graph the equation X + 5y = 10 using intercepts, you will need to find the x-intercept and y-intercept.
To find the x-intercept, you set y equal to zero in the equation and solve for x:
X + 5(0) = 10
X + 0 = 10
X = 10
Therefore, the x-intercept is (10,0).
To find the y-intercept, you set x equal to zero in the equation and solve for y:
0 + 5y = 10
5y = 10
y = 2
Therefore, the y-intercept is (0,2).
Now that you have the x-intercept and y-intercept, you can plot these points on the graph. The x-intercept is (10, 0) and the y-intercept is (0, 2).
To graph the equation X + 5y = 10 using intercepts, you need to find the x and y-intercepts and plot the points on the graph.
To find the x-intercept, you set y = 0 in the equation X + 5y = 10 and solve for x:
X + 5(0) = 10
X = 10
So the x-intercept is (10, 0).
To find the y-intercept, you set x = 0 in the equation X + 5y = 10 and solve for y:
0 + 5y = 10
5y = 10
y = 2
So the y-intercept is (0, 2).
Now, you can plot these points on the graph. Place a point at (10, 0) and another point at (0, 2). These two points represent the x and y-intercepts of the equation.
Finally, draw a straight line passing through these two points. This line represents the graph of the equation X + 5y = 10.