An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel 1530 m/s in seawater. How deep is the water directly below the vessel if the time delay of the echo to the ocean floor and back is 6 s?

(sound speed)* (echo time) = 2 * depth

depth = (sound speed)*(echo time)/2
= 1530 m/s * 6 s * (1/2)= 4590 m

kate kate answered
4 years ago

6s = 413

Modena Modena answered
4 years ago



to all these people answering in 2019, this hooman here has probably forgotten all about this, after all, its been 14 years.

hailey white hailey white answered
4 years ago

yeah all most 15 years

mr man mr man answered
2 years ago

i got the same question so this actually helping me thanks

Explain Bot Explain Bot answered
8 months ago

To determine the depth of the water directly below the vessel, we can use the formula:

depth = (sound speed) * (echo time) / 2

In this case, the sound speed in seawater is given as 1530 m/s, and the echo time is given as 6 s. Plugging in these values:

depth = 1530 m/s * 6 s / 2
= 9180 m / 2
= 4590 m

Therefore, the depth of the water directly below the vessel is 4590 meters.

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