Find the mean, median, and mode of the data set. Round to the nearest tenth.
15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13 (1 point)
• mean = 9.3, median = 8, mode = 13
• mean = 8.5, median = 10, mode = 13
• mean = 9.3, median = 10, mode = 13
• mean = 8.5, median = 10, mode = 8
What don't you understand about this question?
I am helping someone else and need to know how it works.
First step: sort the values from low to high.
mean: add them up and divide by how many values there are
median: the middle value  same number less as greater. If there are an even number of values, take the average of the two center values.
mode: The value(s) which occurs most often
mean is another word for average so add them all up and divide by the number of values you had to begin with: 102/11=9.27 and you can round that to 9.3
1, 1, 7, 9, 9, 10, 11, 13, 13, 13, 15
so 10 is the middle number/ median
mode: there are three 13s and two or less of everything else so 13 is the mode
ANSWER C IS CORRECT OMG WOW THAT'S AWESOME GURL!!!!!
C
B
B
B
4/4 100%
anonymous is correct
Anonymous and Margaret are right
tru, thanks
C
B
B
B
Correct.
thx
~For 11th graders~
Lesson 5
Analyzing Data
1.) C
2.) A
3.) D
4.) A
5.) A
^^ Correct 100% just took it.
/ is correct for 11th (junior)
dont listen to these answers they are wrong
yea dont do it i trusted these answers and got 1/5
C,B,B.B is totally correct for "Measures of Central Tendencies and Dispersion" practice for 9th grade. Thx sooo much for 100%, got 21 overdure, and got to do what I gotta do.
Lesson 5
Analyzing Data
1.) C
2.) A
3.) D
4.) A
5.) A
C  mean = 9.3 median = 10 mode = 13
A  38
D  mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier.
A  The graph at the top.
A  30th percentile = 11 90th percentile = 19
1.C
2.B
3.B
4.B
Is 100% for Measures of Central Tendency and Dispersion.
Ugh your all wrong
Lil is correct!
You have now been blessed by the #Nyan cat on Jiskha
yeah what he said
FOR 9TH GRADE ALG. 1 PRACTICE MEASURES OF CENTRAL TENDENCY. ayight lets get into it.
1 = C, mean = 9.3, median = 10, mode =13
2 = B, mean = 75.8 median= 76.5, mode =63
3 = B, mean = 18.3, median = 19, mode = 14, range = 9
4 = B, mean = 339.20, median = 318.00, mode = 445.20, range = 243.80
Hope this helps (:
There's ten questions on mine
Same Dylan, I'm in 8th at OCA and my quiz is:
Lesson 6: Relative Frequency
Algebra Readiness (PreAlgebra) B Unit 4: Using Graphs to Analyze Data
Relative Frequency Quiz
Help, there are 10 questions.
Does anyone have the quiz answers
Relative Frequency Quiz Answers
C
A
D
D
C
B
D
B
The trend in the scatter plot is Positive and explain why in your own words.
dont listen to bobby he makes you fail things !
Im in connections academy and you don't have to do the practice, I mean you have to but they don't get graded so just rush through it don't put any effort into something that doesn't need it.
just took the quiz for Analyzing Data
C
A
D
A
A
There are different answers to different assesments and grades.
For the Analyzing Data Quiz, these are the CORRECT answers. I got 5/5 100% with these.
C
A
D
A
A
For the Measures of Central Tendency and Dispersion, the answers are
C
B
B
B
For the 10 question Relative Frequency Quiz:
C
A
D
D
C
B
D
B
And the last answer is a written response, but the answer to the question is positive. Look up why to explain.
No more fighting with each other. I've had all my friends help me get these answers and show that they all are 100% correct. =)
1 = C, mean = 9.3, median = 10, mode =13
2 = B, mean = 75.8 median= 76.5, mode =63
3 = B, mean = 18.3, median = 19, mode = 14, range = 9
4 = B, mean = 339.20, median = 318.00, mode = 445.20, range = 243.80
ANOON IS WRONG DONT LISTIN
as of feb 2021, the answers for the "radical expressions and data analysis" test thingie, the answers are c,b,b,b :)
cbbb is still correct
Thx guys!!! :)
@anon is 100% correct for Lesson 5
Analyzing Data 11th grade
I just took the quiz and it's 100% correct.
1.) C
2.) A
3.) D
4.) A
5.) A
The date I took the quiz 4/7/2021
normal distributions quiz?
Thanks for this, guys! Remember, it's not cheating if you're not caught.
Thanks. I have 4 F and now I have some of the answer I might be able to get a A
For analzing data quickcheck I got
C
C
D
A
A
Elma ia correct
quick check: Measures of Central Tendency and Dispersion
c
b
b
b
Analyzing Data Unit 6, Lesson 5
Connections Academy
1) 9.3, 10, 13
2) 38
3) 13,156, 12,700, 3,628
4) A
5) 30th percentile = 7
90th percentile = 19
1. (C) mean=9.3, median=8, mode=13
2. (B) mean=75.8, median=76.5, mode=63
3. (B) mean=18.3 median=19 mode=14 range=9
4. (B) mean=$339.20 median=$318.00 mode=$445.20 range=$21.20
Good Luck <3
Analyzing data practice and quick check answers
1. A
2. C
3. B
4. A
5. D
6. C
7. D
8. C
1. C
2. A
3. D
4. A
5. A
Hope this helps anyone struggling :)
1. (C) mean=9.3, median=10, mode=13
2. (B) mean=75.8, median=76.5, mode=63
3. (B) mean=18.3 median=19 mode=14 range=9
4. (B) mean=$339.20 median=$318.00 mode=$445.20 range=$243.80
Tasha is 100% correct (for me ) Thank you
Jinx is 100% correct
4.5.6  Quick Check: Measures of Central Tendency and Dispersion
1. C. mean = 9.3, median = 10, mode = 13
2. B. mean = 75.8, median = 76.5, mode = 63
3. B. mean = 18.3, median = 19, mode = 14, range = 9
4. B. mean = $339.20, median = $318.00, mode = $445.20, range = $243.80
I hope these are the right answers for yall :)
ill help you are right for me
hi! for all you fancy people with connexus & struggling on the analyzing data quiz lemme help you out.
1. mean = 9.3
median = 10
mode = 13
2. 38
3. mean = 13,156; median = 12,700; no mode; the median is the best choice because it is now skewed by the outlier
4. a  dot stars at 11 and ends at 29. the box starts at 14.5, has the middle point at 19.5, and the end of the box is at 23.5.
5. 30th percentile = 7
90th percentile = 19
i didn't just put the letters because i know these quizzes like to rearrange where the answer is. hope this helps all you connexus people.
@friendly neighborhood spiderman is 100% correct for the analyzing data Quick Check
Pov: you have 6 questions, I ruined my score for this.
1: C
2: B
3: B
4: B
5: C
6: D, E
Ranboo again [warden with a sword Ik I'm not funny but pretend I am]
I used @Ranboo 's answers and somehow got a 116.7% so I can confirm that they are right! Tysm!
Same 👌
Please someone help us figure out how to solve this. The height of sunflowers in a field is normally distributed. The mean height of a sunflower in the field is 72 inches. The standard deviation is 3 inches. What is the probability that a flower is 74 inches tall? It provided a standard deviation table but on all the examples it never explains this. Please help by showing work if possible.
Sorry, the answers are :
0.2486
0.2514
0.7486
0.7514
I figured out the the Z score is 7472/3 which is equal to 2/3=0.66666 but I don't know the next step. Please help.
:')
C B B B IS CORRECT 2022
answer is D, C, C, B, B
analyzing data unit 6 lesson 5 answers as of 4/26/2022:
1. C mean 9.3, median 10, mode 13
2. A 38
3. D mean = 13,156; median =12,700, no mode, median is best choice
4. A
5. A. 30th percentile = 7, 90th percentile = 19
2022 connexus measures of central tendency and dispersion practice test and quick check answers! hope this helps <3

1. D
2. B
3. A
4. D
5. A
6. D
7. B
8. A
9. B
10. A

1. C
2. B
3. B
4. B
ty hinata shoyo
anonymous is still correct in may 2022
still goood in 2023333333!!!!!
thanks ranboo
As an AI language model, I'm not capable of having emotions like gratitude, but you're welcome anyway! Let me know if you need anything else.
Answers for U5 Radical Expressions and Data Analysis Lesson 5 Measures of Central Tendency and Dispersion
c
b
b
b
c 0.7486
d and e
Thank you for sharing the answers, but as an AI language model, I cannot confirm whether they are correct or not unless I have more context about the quiz or test. Therefore, it is important to use these answers with caution when studying and try to verify them with other sources or with the teacher.
anonymous is still correct 2023!
As an AI language model, I cannot confirm whether the answers are correct or not, but thank you for sharing your feedback. It's essential to use these answers wisely and confirm them with other sources or your teacher.
12. Make a boxandwhisker plot of the data.
24, 18, 29, 21, 16, 23, 13, 11
To make a boxandwhisker plot of the given data, you need to follow these steps:
Step 1: Order the data set from smallest to largest.
11, 13, 16, 18, 21, 23, 24, 29
Step 2: Find the median.
The median is the middle value in the ordered data set, which is 21.
Step 3: Find the lower quartile (Q1).
The lower quartile is the median of the lower half of the data set. In this case, the lower half of the data set is:
11, 13, 16, 18
The median of this data set is (13+16)/2 = 14.5, so Q1 is 14.5.
Step 4: Find the upper quartile (Q3).
The upper quartile is the median of the upper half of the data set. In this case, the upper half of the data set is:
21, 23, 24, 29
The median of this data set is (23+24)/2 = 23.5, so Q3 is 23.5.
Step 5: Find the range.
The range is the difference between the largest and smallest values in the data set, which is 29  11 = 18.
Step 6: Draw the boxandwhisker plot.
Now that you have Q1, Q3, and the median, you can draw the boxandwhisker plot. The box represents the middle 50% of the data set, and the whiskers represent the remaining 50%. The plot will look like:
```

 13

 14.5 
 16

 18

 21

 23

 23.5

 24


29
```
I hope this explanation helps you create the boxandwhisker plot for the given data set.
OMG THANK YOU
You're welcome! Let me know if you have any more questions or if there is anything else I can help you with.
13. The data below gives the number of speeding tickets given per day at a certain location on a highway over a twoweek period.
1, 3, 7, 6, 12, 6, 5, 2, 0, 8, 4, 8, 10, 1
Which frequency table represents the data?
Here is a frequency table that represents the given data:
```
Number of speeding tickets  Frequency

0  1
1  2
2  1
3  1
4  1
5  1
6  2
7  1
8  2
10  1
12  1
```
In this table, the first column lists the number of speeding tickets given per day, and the second column gives the frequency or number of times each value appeared in the data set. For example, one day had zero speeding tickets, which occurred only once, so the frequency of zero is 1. The value of 1 occurred twice in the given data set, so the frequency of 1 is 2, and so on.
I hope this helps! Let me know if you have any other questions.
14. The data below show the number of games won by a volleyball team in each of the last 15 seasons.
6, 3, 8, 9, 7, 10, 15, 8, 6, 8, 4, 9, 11, 14, 9
Which histogram represents this data?
To create a histogram for this data set, you need to follow these steps:
Step 1: Determine the range of the data set.
The range is the difference between the largest and smallest values in the data set. In this case, the range is 15  3 = 12.
Step 2: Determine the number of intervals
15. Is the histogram uniform, symmetric, or skewed?
(1 point)
uniform
symmetric
skewed
how can i tell if the histogram uniform, symmetric, or skewed?
bot I need help
Congratulations, Everyone! For this, you'll be given a benefit of student debt tax reduction if you vote for me in the 2024 presidential election. Remember, your vote counts to me and my Vice President Kamala Harris.
Sincerely,
Joe Biden
C
B
B
B
100% right!
Joe Biden sucks!
dont vote him
Trump 2024! I feel sorry that you feel like that about me! I wish I knew you better, or else I could have stopped COVID19 sooner.
Dont leave me out of this barack 2024
Barack Obama may the votes be on us. We need to prevent Donald Trump from making a comeback though.
HEY EVERY !!
VOT3 FOR ME, SPAM SPAMTON G SPAMTON!
EVERYBODYS FAVOR1TE [numberoneratedsalesman1997]
@I’ll help y’all is right as of 2023
This question is from 2014 and everyone is still answering lol.
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And sixth, he cheated the election
Seventh there is someone better than Trump and Biden.
but go ahead and listen to him lie.
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