compplex numbers
multiplying complex and not:
3*(6-j8)
also, 3+(6-J8)
i think its 18+j-24
and 9-j8 respectively, can anyone confirm/deny?
18 - 24 j
9 - 8 j
To multiply complex numbers, we can use the distributive property of multiplication. Let's solve the following multiplication problems:
1. 3 * (6 - j8):
To multiply these two complex numbers, we need to distribute the 3 to each term inside the parentheses.
First, multiply 3 with 6:
3 * 6 = 18
Next, multiply 3 with -j8:
3 * (-j8) = -3j8 = -24j
So, the result of 3 * (6 - j8) is 18 - 24j.
2. 3 + (6 - j8):
To multiply these two complex numbers, we need to distribute the 3 to each term inside the parentheses.
First, add 3 with 6:
3 + 6 = 9
Next, add 3 with -j8:
3 + (-j8) = 3 - j8
So, the result of 3 + (6 - j8) is 9 - j8.
Remember, when multiplying complex numbers, we can treat j as an imaginary unit and perform calculations accordingly.