# A sample of O2 gas was collected over water at 23 degrees celsius and 772 torr. what is the partial pressure of the O2?

## 772 torr - 21.2 torr H2O= 751 torr O2

## To find the partial pressure of O2 in this scenario, we need to subtract the vapor pressure of water at 23 degrees Celsius from the total pressure.

The vapor pressure of water at 23 degrees Celsius is 21 torr.

Therefore, the partial pressure of O2 can be calculated as:

Partial Pressure of O2 = Total Pressure - Vapor Pressure of Water

= 772 torr - 21 torr

= 751 torr

So, the partial pressure of O2 is 751 torr.

## To find the partial pressure of O2, you need to consider the vapor pressure of water at the given temperature. The vapor pressure of water depends on temperature and can be looked up in a reference table or calculated using an equation.

At 23 degrees Celsius, the vapor pressure of water is 21.1 torr. Therefore, the partial pressure of O2 can be calculated by subtracting the vapor pressure of water from the total pressure.

Partial Pressure of O2 = Total Pressure - Vapor Pressure of Water

Given:

Total Pressure = 772 torr

Vapor Pressure of Water = 21.1 torr

Partial Pressure of O2 = 772 torr - 21.1 torr

Partial Pressure of O2 = 750.9 torr

Therefore, the partial pressure of O2 is 750.9 torr.