What is the total internal kinetic energy of 16.2 moles of a monatomic ideal gas at a temperature of 279 K?
KE =
To calculate the total internal kinetic energy (KE) of a monatomic ideal gas, you can use the equation:
KE = (3/2) * n * R * T
Where:
- KE is the total internal kinetic energy,
- n is the number of moles of the gas,
- R is the ideal gas constant (8.314 J/(mol·K)),
- T is the temperature of the gas in Kelvin.
In this case, you have a gas with 16.2 moles (n = 16.2) and a temperature of 279 K (T = 279 K).
Now let's plug in the values into the equation:
KE = (3/2) * 16.2 * 8.314 * 279
First, multiply the mole value (16.2) by the ideal gas constant (8.314) and the temperature (279). Then, multiply the result by (3/2).
KE ≈ 184,135.34 J
Therefore, the total internal kinetic energy of 16.2 moles of a monatomic ideal gas at a temperature of 279 K is approximately 184,135.34 J.