Please show me the steps and solve.
3x+5y=1025
x+5=275
3x+5y=1025
x+5=275
x = 270
3(270) + 5y = 1025
810 + 5y = 1025
5y = 215
y = 43
ah, andra, are you sure you did not mean:
x + 5 y = 275 ???????
Actuaally, it was a word problem and that's the equation I got out of it. Here is the word problem.
Students sold 275 tickets for a fundraiser at school. Some tickets are for the children and cost $3 while the rest are adult tickets that cost $5. If the total value of all the tickets sold was $1025, how many of each ticket were sold? To help you solve this problem, write a linear equation.
3 c + 5 a = 1025
c + a = 275
so c = (275 -a)
3 (275-a) + 5 a = 1025
825 - 3 a + 5 a = 1025
2 a = 100
a = 100 and c = 275-100 = 175
To solve the system of equations:
Equation 1: 3x + 5y = 1025
Equation 2: x + 5 = 275
Step 1: Solve Equation 2 for x
Subtract 5 from both sides of the equation:
x = 275 - 5
x = 270
Step 2: Substitute the value of x (270) into Equation 1
3(270) + 5y = 1025
810 + 5y = 1025
Step 3: Isolate the variable y
Subtract 810 from both sides of the equation:
5y = 1025 - 810
5y = 215
Step 4: Solve for y
Divide both sides of the equation by 5:
y = 215 / 5
y = 43
Therefore, the solution to the system of equations is x = 270 and y = 43.