A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?
V = Vo + a*t = 0
43 + a*0.28 = 0
0.28a = -43
a = -153.6 m/s^2
To find the magnitude of the hailstone's acceleration in the water, we can use the following formula:
acceleration = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 43 m/s
Final velocity (v) = 0 m/s
Time (t) = 0.28 s
Substituting the values into the formula, we get:
acceleration = (0 m/s - 43 m/s) / 0.28 s
Now, let's calculate the acceleration:
acceleration = (-43 m/s) / 0.28 s
Simplifying the expression:
acceleration ≈ -153.57 m/s²
Therefore, the magnitude of the hailstone's acceleration in the water is approximately 153.57 m/s².