Evaluate the permutation.
P(5, 5)
a. 1 b. 120 c. 0 d. 4
I searched Google under the key words "permutations" to get these possible sources:
http://en.wikipedia.org/wiki/Permutation
(Broken Link Removed)
http://mathforum.org/dr.math/faq/faq.comb.perm.html
In the future, you can find the information you desire more quickly, if you use appropriate key words to do your own search. Also see http://hanlib.sou.edu/searchtools/.
I hope this helps. Thanks for asking.
To evaluate the permutation P(5, 5), we can use the formula for permutations:
P(n, r) = n! / (n - r)!
In this case, n = 5 and r = 5, so we can substitute these values into the formula:
P(5, 5) = 5! / (5 - 5)!
= 5! / 0!
Since any number divided by 0 is undefined, the denominator becomes 0! which is equal to 1. Therefore, we have:
P(5, 5) = 5! / 1
= 5!
Now, we can find the value of 5! (5 factorial) which is:
5! = 5 x 4 x 3 x 2 x 1
= 120
Therefore, the permutation P(5, 5) is equal to 120.
So, the correct answer is b. 120.