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X10
Answers (19)
FLu sorry for late reply. My Internet not working for past 20 hrs. Anyhow I'm sorry for the time up. But the mistake u were doing is that E_o is ur maximum amplitude value in the given equation not permitivity constant.like in my case E_o= 55 in
Problem 1: part f: Bo= E_0/speed u got in case 1 or case2
Part a and Part c: d/dt (l (sin((k lambda)/4-t omega)+sin(t omega)))/k where t=2.4*10^-16; omega=3.83*10^15; k=12775810.12; lambda=4.91*10^-7;l=1 Put this value in wolframalpha and divide the result by speed of light and for Part b: Integrate[Cos[k z -
Δω=sqrt(3)*R/L
C part please..
Yup just stuck with last part
Standing wave last part anyone ??
How to do part e ??
I've solved RL circuits using circuit simulator software. Anyhow for Q4 part - a) I1=0,I2=V/(2R+R) part - b) I1=V/2R,I2=0 These formula can be used but I haven't used these..
For Bz quest:5 0 0 mu_0*i/4r where m_0= 4*pi*10^-7 and r=a please convert cm to m
Thankyou guys...specially that Anonymous person who provided the correct formula for calculating B in the last question and so mid is over now.. last quest part b: B=[(2*mu_0)/(3*z^3)]*(R^4)*sigma*omega
Q5: mu_0*i/4r where m_0= 4*pi*10^-7 and r=a please convert cm to m
for q3 part c use the Bo not the one derived in part a...and for q6 make sure u have converted the values in m from cm
Q6: ((mu_0*I)/2*pi*w)*ln(1+(w/x)) .... (I = J*w*s) and convert cm to m.
Q:3 for part a: B=E/v for part b: (L^2+h^2)/2L for part c: m=rqB/v
I've solved all problems just got stuck with this one...
Yup I've got I correct it is: 8.4*10^-3 sigma= 7 ×10−4C m−2, ω= 6 rad⋅s−1, z= 1.9 m and R=1m and B as i calculated: 4.66*10^-10 but the grader is not accepting it
@FLu let me know if u got the correct answer with this formula and what it is ?
@anon this formula works for my friend but not for me I don't know what is the problem going on perhaps the formula isn't derived correctly...:(
