Juri

Questions and answers by Juri

Questions (10)

There are two solutions to | 16x - 5 | = 3. The greatest solution is ___.Since the expression, 16x - 5, can be either positive
1. 2 answers
2. 1,395 views
How do I factor out:21 - 4x - x^2 x^2 + 4x - 21 = 0 this is of the form (ax + c)(bx + d) = abx^2 + (c+d)x + cd here ab = 1 so
1. 1 answer
2. 308 views
(2x^2 + 10x + 12) divided by (x + 3)your question is (2x^2 + 10x + 12)/(x + 3) =2(x+2)(x+3)/(x+3) = can you take it from here?
1. 1 answer
2. 365 views
Using synthetic division:x^3 + 4x^2 - 3x - 12 / x^2 - 3 Write it out like a long division problem. x^-3 goes into x^3 + 4x^2 -3x
1. 3 answers
2. 604 views
Factor out:64x^3 + 1 It is a binomial times a trinomial (4x+1)(16x^2-4x+1) should work. Check my math again! [8x^(3/2) -
1. 1 answer
2. 431 views
Factor out:1-125b^3 5b -1 is one of the factors. (Consider that an informed guess). Divide that into 1-125b^3 for the other
1. 1 answer
2. 968 views
Divide 1-125b^3 by 5b - 1You need to learn the technique of polynomial long division. It's just the same as if numbers were
1. 1 answer
2. 456 views
Factor out 8x^3y^6 + 27One factor is 2xy^2+3. (The sum of the cube roots of the first and last terms). Use long division to
1. 1 answer
2. 435 views
Simplify (b^3)(ab-1)((ab)^2+ab+1)Hint: The last two factors sure look like the difference of two cubes to me. Have you tried
1. 1 answer
2. 363 views
Simplify (2xy^2+3)((2xy^2)^2-(2xy^2)(3)+(3)^2)This reminds me of (U+a)(U^2- aU + a^2). When mulipltiplied out, one gets a cubic
1. 2 answers
2. 564 views