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Den
Questions (16)
Write each power as a product of the same factor.
5^4 a. 5 × 5 × 5 × 5 b. 4 × 4 × 4 × 4 × 4 c. 5 × 5 × 5 × 5 × 5 d. 5
5 answers
1,350 views
Define a variable and write an expression for the phrase.
the quotient of 6 times a number and 16 a.(16x) / 6 b.(6x) / 16 c.96x
5 answers
1,985 views
Evaluate each expression.
9 ¸ 3 + 3 ´ 4 a. 24 b. 15 c. 17 d. 6 MY ANSWER 15??????
3 answers
355 views
Evaluate each expression.
7 + (3 + 12 / 2)^2 a. 16 b. 88 c. 46 d. 256 I think 88 ????????
1 answer
336 views
Which shows the expression below simplified?
(3.6 × 1015) + (1.8 × 1012) a. 3.60018 × 1015 b. 3.902 × 1014 c. 3.618 × 1015
3 answers
524 views
Which shows the expression below simplified?
(3.6 × 10^15) + (1.8 × 10^12) a. 3.60018 × 10^15 b. 3.902 × 10^14 c. 3.618 ×
1 answer
421 views
3 - 15 × 5
a. 90 b. 0 c. –72 d. 78
5 answers
334 views
Simply reporting measures of central tendency or measures of variability will not tell the whole story. Using the following
2 answers
586 views
Arrange the following atoms in order of increasing size from smallest to largest.
Phosphorus Fluorine Chlorine Sulfur
4 answers
3,060 views
Weight of the mustard package Sample: 3.02 (g)
Weight of the mustard package Solution: 33.3 (g) Trial #1 Trial #2 Trial #3 Weight
7 answers
517 views
Weight of the mustard package Sample: 3.02 (g)
Weight of the mustard package Solution: 33.3 (g) Trial #1 Trial #2 Trial #3 Weight
1 answer
851 views
n the titration of 25.00 ml of a water sample, it took 20.590 ml of 4.995x10-3 M EDTA solution to reach the endpoint. Complete
3 answers
1,262 views
At Smith's club the pay-per-visit fee is $5 per day. would Smith save money paying per visit? Assume that a month has 4.3 weeks.
2 answers
614 views
10 A color candy was chosen randomly out of a bag. Below are the results:
Color Probability Blue 0.30 Red 0.10 Green 0.15 Yellow
2 answers
769 views
If a strong acid or base is dissolved in water, will all of its parts have the concentration?
For example in Ca(OH)2 = Ca + 2OH
3 answers
469 views
"For 4HCl + O2 <-> 2Cl2 + 2H2O :
If in a container of 1.0 L we start with 2 moles of O2 and 4 moles of HCl, the molar fraction of
10 answers
848 views
Answers (15)
I see, thank you so much for the help! I didn't expect anyone to answer and less reply continuously haha. I'm very grateful! Thank you once again and have a great day!
So all 2 moles of O2 are used for the molar fraction formula even though only one of its moles can react to the 4 moles of HCl because '-x' is being added to it?
I went back to look at my procedure and I noticed I made an error in the second one, I actually got (1-x / 5-x) , which is one of the choices. Could that be the answer? Or do we have to take into account all moles of O2 despite the proportion given in the
They want O2 after equilibrium is reached. The problem doesn't give me the equilibrium constant. And I suppose x would be the unknown value you put when you're writing the ICE table? for example there are 2 moles of O2 at the beginning, x would be the
299.49 J
After getting this, in order to convert the three masses into moles, what do I divide each mass by
mustard solution, how would i calculate the mass of naOH used?
Forget it i got the answer
60 mph, i think. i first found the radius (since it's the same for both) then calculated the speed for curve b
-72 ?????
Sorry! Which shows the expression below simplified? (3.6 × 1015) + (1.8 × 1012) a. 3.60018 × 10^15 b. 3.902 × 10^14 c. 3.618 × 10^15 d. 3.6018 × 10^15
I don't understand.????
15 ITS RIGHT?
I DON'T KNOW. b.???
Ok!Thanks