if there are x bags of flour, then
2(x+3) + 5x = 48
2(x+3) + 5x = 48
So, I have the answer choices, so I know what to do.
A) 9 bags of sugar and 10 bags of flour.
Sugar is 2 pounds. So 9X2= 18
Flour is 5 pounds, which is 10X5=50
50+18=68 That is not 48 pounds. Moving on.
B) 4 bags of sugar and 8 bags of flour.
We know the drill, so let's go!
4X2=8
8X5=40
40+8=48
Yay! B is correct. There is your answer. Hope this helped!
From the given information, we can form two equations:
1) Sugar comes in 2-pound bags, so the weight of sugar purchased is 2S.
2) Flour comes in 5-pound bags, so the weight of flour purchased is 5F.
According to the problem, Thomas bought 3 more bags of sugar than flour, so we can write another equation:
3) S = F + 3
The total weight purchased is 48 pounds, which is the sum of the weights of sugar and flour. So we can write one more equation:
4) 2S + 5F = 48
Now we have a system of equations. We can substitute the value of S from equation 3 into equation 4 and solve for F:
2(F + 3) + 5F = 48
2F + 6 + 5F = 48
7F + 6 = 48
7F = 42
F = 42/7
F = 6
By substituting the value of F back into equation 3, we can find the value of S:
S = 6 + 3
S = 9
Hence, Thomas bought 9 bags of sugar and 6 bags of flour.