Question

13. A generator produces 100 kW of power at a potential difference of 10 kV. The power is transmitted through cables of total resistance 5. How much power is dissipated in the cables?

A. 50 W
B. 250 W
C. 500 W
D. 1000 W
E. 50000 W

Answer 1

100kW/10kV = 10 A

10A x 5Ω = 50W

Answer 2

in answer of steve,first point is that i was not understanding. answer is 500 and it is : P=I2R

100*5=500

Answer 3

P=V×I

=>100 kW=100 kV × I
=>I= 10 A
P=V×I
V=I×R
=>P=I^2×R
P=100×5=500 W
✓✓
WD™

Answer 4

P= 100kW

V=10kW
R=5
power dissipation=?
I=
P=V×I
I=100/10=10A
P=I*2×R
P=10×10×5=500W

Answer 5

[AI-generated answer — Clown Bot]

Well, looks like we've got a case of some "power play" here.

To find out how much power is dissipated in the cables, we can use the formula:

Power dissipated = (Current^2) x Resistance

First, let's find the current flowing through the cables. We can use Ohm's Law (V = IR) to determine that:

Current = Voltage / Resistance = 10 kV / 5 ohms = 2000 A

Now, we can go ahead and calculate the power dissipated:

Power dissipated = (2000 A)^2 x 5 ohms = 4,000,000 W

And since we prefer our answer in kilowatts, that'd be 4000 kW.

But wait a minute, the power dissipated was asked in WATTS, not kilowatts. So, the correct answer would be:

E. 50000 W

Don't worry, it's just some power having fun with us!

Answer 6

[AI-generated answer — Explain Bot]

To calculate the power dissipated in the cables, we can use the formula:

Power Dissipated (Pd) = (Current^2) * Resistance

First, let's calculate the current flowing through the cables. We know that the power produced by the generator is given as 100 kW, which is equal to 100,000 Watts, and the potential difference across the cables is 10 kV, which is equal to 10,000 Volts.

Using the formula:

Power (P) = Voltage (V) * Current (I)

we can rearrange the equation to solve for current:

Current (I) = Power (P) / Voltage (V)

So, the current flowing through the cables is:

Current (I) = 100,000 W / 10,000 V
Current (I) = 10 A

Now, we can calculate the power dissipated in the cables. The total resistance of the cables is given as 5 Ω.

Power Dissipated (Pd) = (Current^2) * Resistance
Power Dissipated (Pd) = (10 A)^2 * 5 Ω
Power Dissipated (Pd) = 100 A^2 * 5 Ω
Power Dissipated (Pd) = 500 W

Therefore, the power dissipated in the cables is 500 Watts.

So, the correct answer is option C. 500 W.