F2 = F1 = m * g = 1kg * 9.8N/kg = 9.8 N.
F1 = Force of the book.
F2 = Force of ihe table.
The 2 forces are equal and opposite.
F1 = Force of the book.
F2 = Force of ihe table.
The 2 forces are equal and opposite.
1. Force due to gravity (weight): The weight of the book can be calculated using the equation:
Weight = mass × acceleration due to gravity (g)
Given that the mass of the book is 1.0 kilogram, and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight:
Weight = 1.0 kg × 9.8 m/s² = 9.8 Newtons (N)
2. Force exerted by the tabletop: The force exerted by the tabletop balances the weight of the book, so it must be equal in magnitude but opposite in direction. Therefore, the magnitude of the force of the tabletop on the book is also 9.8 Newtons (N).
Therefore, the magnitude of the force of the tabletop on the book is 9.8 Newtons (N).
In this scenario, there are two main forces acting on the book: the force of gravity pulling it downward and the normal force exerted by the tabletop upward.
The force of gravity, also known as the weight of the book, can be calculated using the equation:
Weight = Mass * Acceleration due to gravity
Given that the mass of the book is 1.0 kilogram and the acceleration due to gravity is approximately 9.8 m/s², we can calculate the weight:
Weight = 1.0 kg * 9.8 m/s² = 9.8 Newtons
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. So, the magnitude of the force of the tabletop on the book will be equal and opposite to the weight of the book, which is 9.8 Newtons.
Therefore, the magnitude of the force of the tabletop on the book is 9.8 Newtons.