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To write the reactant equations and solve for the mass of CO2 produced when 1 kg of CaCO3 is heated to obtain 560 g of CaO, we need to understand the balanced chemical equation for the reaction between CaCO3 and heat.
The balanced chemical equation for the thermal decomposition of calcium carbonate (CaCO3) is as follows:
CaCO3(s) → CaO(s) + CO2(g)
From the equation, we can see that 1 mole of CaCO3 produces 1 mole of CaO and 1 mole of CO2.
To solve for the mass of CO2 produced, we can follow these steps:
Step 1: Calculate the number of moles of CaO produced.
The molar mass of CaO is 56.08 g/mol (40.08 g/mol for Ca + 16.00 g/mol for O). So, the number of moles of CaO produced can be calculated as:
moles of CaO = mass of CaO / molar mass of CaO
moles of CaO = 560 g / 56.08 g/mol
moles of CaO = 10 mol
Step 2: Since the balanced equation shows that the moles of CaO are equal to the moles of CO2, we can conclude that 10 moles of CO2 are produced.
Step 3: Calculate the mass of CO2 produced.
The molar mass of CO2 is 44.01 g/mol (12.01 g/mol for C + 2x16.00 g/mol for O). So, the mass of CO2 produced can be calculated as:
mass of CO2 = moles of CO2 x molar mass of CO2
mass of CO2 = 10 mol x 44.01 g/mol
mass of CO2 = 440.1 g
Therefore, when 1 kg of CaCO3 is heated to produce 560 g of CaO, approximately 440 g of CO2 is produced.
Note: The assumption made here is that all of the CaCO3 is converted to CaO without any losses or impurities.