Of course, I'd be happy to help you with this physics problem!
To determine the water pressure at the bottom of the 50-meter-high water tower, we can use the concept of hydrostatic pressure. Hydrostatic pressure is the pressure exerted by a fluid at rest due to the weight of the fluid above it. In this case, the fluid is water and the height of the water tower provides the basis for calculation.
Here's how you can calculate the water pressure at the bottom of the water tower:
1. Understand the concept: The relationship between pressure, height (depth), and the density of a fluid is given by the equation: P = ρgh, where P is the pressure, ρ (rho) is the density of the fluid, g is the acceleration due to gravity, and h is the height (depth) of the fluid column.
2. Gather the required information: From the problem statement, we are given that the height of the water tower, h, is 50 meters. We also need the density of water, which is approximately 1000 kg/m³, and the gravitational acceleration, which is approximately 9.8 m/s².
3. Calculate the pressure: Using the equation P = ρgh, we can substitute the known values:
P = (1000 kg/m³) × (9.8 m/s²) × (50 m)
= 490,000 N/m²
Therefore, the water pressure at the bottom of the 50-meter-high water tower is 490,000 N/m² or 490,000 pascals (Pa). We can also approximate this value as approximately 500 kilopascals (kPa).
If you have any further questions regarding this problem or any other physics concepts, feel free to ask!