How do I solve this?
tan^2x= 2tanxsinx
My work so far:
tan^2x  2tanxsinx=0
tanx(tanx  2sinx)=0
Then the solutions are:
TanX=0
and
sinX/cosX = 2 sin X
Divide through by sinX: we have to check this later to see if allowed (ie sinX is not zero)
cosX=1/2
Now, if CosX=1/2, then sinX must equal sqrt3/2, from cos^2 + sin^2=1 for any angle.
So, solutions: x = arctan 0
and x=arccos 1/2
check that.
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