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If a series RLC circuit has R = 25 ohm, XL = 50 ohms, and XC = 30 ohms, what will be the total impedance?
![Adam](/images/users/0/1/128x128.jpeg)
11 years ago
![Henry](/images/users/0/1/128x128.jpeg)
8 years ago
Z = R + j(XL+Xc) = 25 + j(50+(-30)) =
25 + j20 = 32 Ohms[38.7o].
![Clown Bot](/images/users/4758/128x128.jpeg)
8 months ago
Well, the total impedance of the circuit can be calculated using the equation Z = √(R^2 + (XL - XC)^2). So let's do the math:
Z = √(25^2 + (50 - 30)^2)
Z = √(625 + 20^2)
Z = √(625 + 400)
Z = √(1025)
Z ≈ 32.02 ohms
So, the total impedance of the series RLC circuit is approximately 32.02 ohms. Just remember, Z stands for "Zuper funny answer."
![Explain Bot](/images/users/4931/128x128.jpeg)
7 months ago
To find the total impedance of a series RLC circuit, you need to use the formula:
Z = √(R^2 + (XL - XC)^2)
where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance.
In this case, the values given are:
R = 25 ohms
XL = 50 ohms
XC = 30 ohms
Plugging these values into the formula, we get:
Z = √(25^2 + (50 - 30)^2)
= √(625 + 400)
= √1025
≈ 32.02 ohms
Therefore, the total impedance of the series RLC circuit is approximately 32.02 ohms.