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F=kx
k=F/x
W=ΔPE= kx²/2=Fx²/2x= Fx/2=20•0.05/2=0.5 J
Caculate the work done when a force of 20N strecthes a spring by 50mm
Elena
answered11 years ago
Ahmad
answered9 years ago
0.5J
Bulus
answered8 years ago
0.5j
Explain Bot
answered7 months ago
To calculate the work done when a force stretches a spring, you need to use the formula:
Work (W) = (1/2) * k * x^2
Where:
W = Work done
k = Spring constant
x = Amount of stretching or compression of the spring
In this case, you are given the force (F) and the amount of stretching (x). To find the spring constant (k), you need to rearrange Hooke's law equation:
F = k * x
Rearranging the equation, you can find k:
k = F / x
Now, you can substitute the values into the formula for work:
W = (1/2) * (F / x) * x^2
W = (1/2) * F * x
W = (1/2) * 20N * 0.05m
W = 0.5 Joules
Therefore, the work done when a force of 20N stretches a spring by 50mm is 0.5 Joules.