Find the time constant RC first.
1/2=e^(-t/RC) solve for RC
Then,
1/16=e^-t/RC, solve for time for a).
a)How much time would it take the capacitor to discharge from its max charge to 1/16th of that max charge?
1/2Qmax => t=1.38s
1/4Qmax => 1.38/(.5)= .276s
1/6Qmax => .276s/(.25) = 1.104 s
b)What is the time constant of this circuit?
I know that time constant = RC but we are given two unknowns the time constant and the capacitance. R would be 100 x 10^9 or 1 x 10^11.
1/2=e^(-t/RC) solve for RC
Then,
1/16=e^-t/RC, solve for time for a).
The time constant (Ï„) of a RC circuit is given by the product of the resistance (R) and the capacitance (C), i.e., Ï„ = RC.
In this case, you are given the resistance (R) as 100 GΩ (which is equivalent to 1 x 10^11 Ω). However, the capacitance (C) is not provided.
To determine the time constant, we need an additional piece of information.