PV=nRT
solve for n. Now knowing the number of moles, you know the mass of n moles, so you can get the mol mass.
solve for n. Now knowing the number of moles, you know the mass of n moles, so you can get the mol mass.
Then use mols = g/molar mass to calculate molar mass. Post your work if you get stuck.
First, we need to convert the given volume from cubic centimeters (cm³) to liters (L) since the unit of R is in liters. We divide the volume by 1000 to convert:
300 cm³ ÷ 1000 = 0.3 L
Next, we need to convert the temperature from Celsius (°C) to Kelvin (K). We add 273.15 to the temperature in Celsius:
25°C + 273.15 = 298.15 K
Now, let's rearrange the Ideal Gas Law equation to solve for the number of moles (n):
n = PV / RT
We have the following values:
P = 92.4 kPa (convert to atm by dividing by 101.325)
V = 0.3 L
R = 0.0821 (the ideal gas constant in atm L/mol K)
T = 298.15 K
Plugging in the values, we get:
n = (92.4 kPa / 101.325) * (0.3 L) / (0.0821 (atm L/mol K) * 298.15 K)
Simplifying the equation gives us the number of moles (n).
Finally, to find the molecular weight (molar mass) of the gas, we divide the mass of the gas (given as 3.73 g) by the calculated moles:
Molecular weight = mass of gas / number of moles.
So, divide 3.73 g by the calculated number of moles to get the molecular weight of the gas.