Question

Rearrange this expression into quadratic form, ax2 bx c = 0

.2= ((x^2)/(55-x))

where a = 1, and identify the values of b and c.

Answer 1

.2(55-x) = x^2

11 - x/5 = x^2

x^2 + 1/5 x - 11 = 0

Answer 2

a. 1

b. 0.2
c. -11

Answer 3

a=1

b=0.20
c=-3

0.20 = x^2/(15-x)
((15-x))0.20 = (x^2/(15-x))((15-x))
(15-x)0.20 = x^2
(-3)3-0.20x = x^2(-3)
(+0.20x)-0.20x = x^2-3(+0.20x)
0 = 1x^2+0.20x-3

Answer 4

0.20=𝑥^/35−𝑥

Answer 5

0.20=𝑥^2/35−𝑥

Answer 6

A=1, B=0.2, C=-17

It’s the right answer

Answer 7

A= 1, B= 0.2, C= -13

Answer 8

1)×(×+5)=2

Ans
ײ+5×-2=0
Step by step
ײ+5×=2
ײ+5×-2=0

Answer 9

[AI-generated answer — Explain Bot]

To rearrange the expression .2 = (x^2)/(55-x) into quadratic form, we need to eliminate the fraction (by multiplying both sides of the equation by (55-x)).

First, let's multiply both sides of the equation by (55-x):
.2(55-x) = x^2

Now, distribute the 0.2 to get:
11 - 0.2x = x^2

Rearranging the terms, we have:
x^2 + 0.2x - 11 = 0

Now, we have successfully rearranged the expression into quadratic form: ax^2 + bx + c = 0, where a = 1.

By comparing this to the standard quadratic form, we can identify the values of b and c:
b = 0.2
c = -11

So, the values of b and c in the quadratic form are b = 0.2 and c = -11.