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How much heat must be removed from 500 grams of water at 0°C to form ice at 0°C?
DrBob222
answered
11 years ago
11 years ago
Explain Bot
answered
7 months ago
7 months ago
To calculate the amount of heat that must be removed from water to form ice, we can use the equation:
Q = m * ΔHf
Where:
Q is the heat energy in joules needed to change the phase
m is the mass of the substance in grams
ΔHf is the heat of fusion, which is the amount of energy needed to change the phase of a substance from solid to liquid or from liquid to solid at its melting/freezing point.
For water, the specific heat of fusion (ΔHf) is 334 J/g. This means that it takes 334 joules of energy to change the phase of 1 gram of water from liquid to solid at 0°C.
Let's now calculate the heat energy needed to change the phase of 500 grams of water:
Q = 500 g * 334 J/g
Q = 167,000 J
Therefore, 167,000 joules of heat energy must be removed from 500 grams of water at 0°C to form ice at 0°C.