I would use the combined gas law
P1*V1/T1 = P2*V2/T2 solve for T2. Temps are in Kelvins.
P1*V1/T1 = P2*V2/T2 solve for T2. Temps are in Kelvins.
V1=3500ml T1=293K P1=650 mmHg V2=8570mL P2=45.6mmHg T2=?
Than I did 3500*650/293k=8750*45.6/X. Then I crossed multiplied and didn't get 230 degree celsius.
and volume has to be converted into liters.. 1000 ml in one liter
and temperature into kelvin.. 0 degrees celcius equals 273 degrees kelvin
i just worked it out and got the right answer
Problem #2 is that the final T comes out in Kelvin. You must subtract 273 to get C. I plugged in all those numbers and I get 503 K which is 230 C. By the way, I notice that the original post lists 8750 mL for the final volume but you used 8570 in the calculation. I used 8570 to get the 503 K.
P1=650 mm
V1 = 3500 mL
T1 = 293
P2 = 456
V2 = 8570
T2 = ?
(650*3500)/293 = (8570*456)/T2
Cross multiply
650*3500*T2 = 8570*456*293
T2 = (8570*456*293)/(650*3500)
T2 = 503 K
T2 in C = 503 - 273 = 230 C