Video rental Store A charges a membership fee of $25 and $2 for each movie rental.
Video rental store b charges a membership fee of $10 and $2.50 for each movie. Find the number of movies rentals for which both stores' charges are the same
Ok how bout if you equate the number of movies each store sold as x and then multiply it by how much it costs to rent a movie at each store. Set up two equations with the member fee included into the equation,one for Store A (use y to represent the total cost)
25 + 2x = y
then do the same for the other eaution
10 + 2.5x = y
no equate them together
25 + 2x = 10 + 2.5x
now all you have to do is solve for x and that will tell you how many movies were sold.
The answer is 30
To find the number of movie rentals for which both store's charges are the same, we need to set up an equation and solve for the number of rentals.
Let's denote the number of movie rentals as "x".
For store A, the total charge can be calculated as:
Total charge for store A = Membership fee + (Cost per movie rental * Number of rentals)
Total charge for store A = $25 + ($2 * x)
For store B, the total charge can be calculated as:
Total charge for store B = Membership fee + (Cost per movie rental * Number of rentals)
Total charge for store B = $10 + ($2.50 * x)
To find the number of rentals where both store's charges are the same, we need to set up an equation and solve for "x".
Total charge for store A = Total charge for store B
$25 + ($2 * x) = $10 + ($2.50 * x)
Now, we can solve for "x".
$25 + ($2 * x) = $10 + ($2.50 * x)
$25 - $10 = ($2.50 * x) - ($2 * x)
$15 = $0.50 * x
To isolate "x", we divide both sides of the equation by $0.50:
$15 / $0.50 = x
x = 30
Therefore, for 30 movie rentals, both store A and store B will have the same charges.