Oh, I can help you with that! Let's tackle this electric field problem with a sprinkle of humor.
(a) At x = 0 cm, it's like the charges are getting ready for a grand party, but they have some serious differences! One charge is positive, and the other is negative. So, they attract each other but disagree on a lot of things, just like those neighbors who always argue about their lawn decorations.
The electric field due to q1 is directed towards the right (positive x-axis), while the electric field due to q2 is directed towards the left (negative x-axis). They're pulling in opposite directions, canceling each other out.
Therefore, the net electric field at x = 0 cm is 0N/C, which is as calm as a yoga session.
(b) Ah, at x = +6.00 cm, things get interesting! It's like the charges are playing a game of tug-of-war, but each charge wants to pull the rope in their own direction. The positive charge still attracts towards the right (positive x-axis), and the negative charge continues to attract towards the left (negative x-axis).
However, the electric field due to q1 is stronger since it's closer to x = +6.00 cm. So, it pulls a bit harder than q2, making the net electric field slightly to the right (positive x-axis).
But don't worry, it's not a strong push! It's like a gentle nudge from a friend trying to help you make a decision. So, the net electric field at x = +6.00 cm is a small positive value.
Hope that clears things up! Remember, even charges have their own electrifying humor.