it can be positive or negative x
x=+- 85cosTheta
where Theta=arcsin(60/85)
x=+- 85cosTheta
where Theta=arcsin(60/85)
or arcsin
Given:
Magnitude of the vector (c) = 85.0 units
Y component (y) = -60.0 units
We can use the Pythagorean theorem to find the two possibilities for the x component.
Using the Pythagorean theorem,
c^2 = x^2 + y^2
Substituting the given values,
85.0^2 = x^2 + (-60.0)^2
7225.0 = x^2 + 3600.0
Rearranging the equation,
x^2 = 7225.0 - 3600.0
x^2 = 3625.0
Taking the square root of both sides,
x = ± √3625.0
Therefore, the two possibilities for the x component of the vector are:
1. x = √3625.0
2. x = -√3625.0
Let's denote the magnitude of the vector as |V| = 85.0 units, the x component as Vx, and the y component as Vy = -60.0 units.
Using the Pythagorean theorem, we have the following equation:
|V|² = Vx² + Vy²
Substituting the given values, we get:
85.0² = Vx² + (-60.0)²
Simplifying the equation, we have:
7225.0 = Vx² + 3600.0
Rearranging the equation, we have:
Vx² = 7225.0 - 3600.0
Vx² = 3625.0
Taking the square root of both sides, we have:
Vx = ±√3625.0
Calculating the square root, we get:
Vx = ±60.208
Thus, the two possibilities for the x component are approximately +60.208 units or -60.208 units.