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A person walks the path shown below. The total trip consists of four straight-line paths.

Path 1 is 40.0 m due east.
Path 2 is 170.0 m due south.
Path 3 is 120.0 m 30.0° south of west.
Path 4 is 190.0 m 60.0° north of west.
At the end of the walk, what is the person's resultant displacement?
( meters and degrees south of west)

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1 answer

  1. 40E = (40,0)
    170S = (0,-170)
    120W30°S = (-103.9,-60)
    190W60°N = (-95,165.5)

    Add them up to get (31.1,-64.5) = 71.6m W64°S

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