Ask questions and get helpful answers.

Use polar coordinates to find the limit. [If (r, θ) are polar coordinates of the point (x, y) with r ≥ 0, note that r → 0+ as (x, y) → (0, 0).] (If an answer does not exist, enter DNE.)

lim (x, y)→(0, 0) [(3e^−x^2− y^2) − 3]/
(x^2 + y^2)

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

1 answer

  1. in polar coordinates, we have

    lim (r->0) (3e^-(r^2)-3)/r^2
    = lim -6re^(-r^2))/2r
    = lim -6e^(-r^2)/2

    as r-> 0, lim = -3

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.